X2+y2+Z^2=2

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Solution for X2+y2+Z^2=2 equation: 



X2+X2+^2=2

We move all terms to the left:

X2+X2+^2-(2)=0

determiningTheFunctionDomain
X2+X2-2+^2=0

We add all the numbers together, and all the variables

2X^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{4}=0$

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